How do you rationalize (2sqrt3 - 3sqrt2)/ sqrt2? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Massimiliano May 8, 2015 In this way: (2sqrt3 - 3sqrt2)/ sqrt2*sqrt2/sqrt2=(2sqrt3*sqrt2-3sqrt2*sqrt2)/2= =(2sqrt6-6)/2=(2(sqrt6-3))/2=sqrt6-3. Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1271 views around the world You can reuse this answer Creative Commons License