How do you prove this ? #sum_(n=1)^oo a_n# converges #-># #sum_(n=1)^oo a_n^2# converges
1 Answer
Jun 5, 2017
The assertion is false.
Explanation:
The assertion is false.
For example:
#sum_(n=1)^oo (-1)^n/sqrt(n)" "# converges
#sum_(n=1)^oo 1/n" "# diverges
