How do you prove that EF || AB ?

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1 Answer
Apr 29, 2018

See the Explanation:

Explanation:

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In triangle ADM,ADM,
angle A + angle M = angle D = alpha + betaA+M=D=α+β

Given angle A = alpha : A=α:
alpha + angle M = alpha + betaα+M=α+β
=> angle M = betaM=β

EM EM is "transversal" transversal crosses AB and EF, angle M = angle E = beta ABandEF,M=E=β
=> AB " || " EF AB || EF