How do you prove log_10 x +log_10(3x-5)=log_10 2?

1 Answer
Cesareo R.
May 18, 2016

Not proof but calculation. {x=-1/3,x=2}

Explanation:

You cannot prove because it is not an identity. You can calculate or solve the proposition. Then let us calculate.
log_ax+log_a(3x-5)-log_a2=log_a((x(3x-5))/2)=0
But log_ay=0->y = 1 So we get as a result
((x(3x-5))/2)=1. Now solving for x we get
{x=-1/3,x=2} two solutions.

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