How do you plot the polar coordinate $(2, \frac{7 π}{6})$ $(2, (7pi)/6)$ ?

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How do you plot the polar coordinate $(2, \frac{7 π}{6})$ $(2, (7pi)/6)$ ?

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Answer 1 · 2017-04-14T08:55:26

To plot $(2, \frac{7 π}{6})$ $(2,(7pi)/6)$ , one should plot point $(- \sqrt{3}, - 1)$ $(-sqrt3,-1)$ in Cartesian plane.

Explanation:

The relation between polar coordinate $(r, θ)$ $(r,theta)$ and Cartesian coordinates $(x, y)$ $(x,y)$ is

$x = r cos θ$ $x=rcostheta$ and $y = r sin θ$ $y=rsintheta$

Hence for $(2, \frac{7 π}{6})$ $(2,(7pi)/6)$ we have $x = 2 \times cos (\frac{7 π}{6}) = 2 \times (- \frac{\sqrt{3}}{2}) = - \sqrt{3}$ $x=2×cos((7pi)/6)=2×(-sqrt3/2)=-sqrt3$ and $y = 2 \times sin (\frac{7 π}{6}) = 2 \times (- \frac{1}{2}) = - 1$ $y=2×sin((7pi)/6)=2×(-1/2)=-1$ .

Hence to plot $(2, \frac{7 π}{6})$ $(2,(7pi)/6)$ , one should plot point $(- \sqrt{3}, - 1)$ $(-sqrt3,-1)$ .

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How do you plot the polar coordinate $(2, \frac{7 π}{6})$ $(2, (7pi)/6)$ ?

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How do you plot the polar coordinate (2, (7pi)/6)(2,7π6)(2, (7pi)/6)?

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How do you plot the polar coordinate $(2, \frac{7 π}{6})$ $(2, (7pi)/6)$ ?