How do you plot the polar coordinate #(2, (7pi)/6)#?

1 Answer
Shwetank Mauria
Apr 14, 2017

To plot #(2,(7pi)/6)#, one should plot point #(-sqrt3,-1)# in Cartesian plane.

Explanation:

The relation between polar coordinate #(r,theta)# and Cartesian coordinates #(x,y)# is

#x=rcostheta# and #y=rsintheta#

Hence for #(2,(7pi)/6)# we have #x=2×cos((7pi)/6)=2×(-sqrt3/2)=-sqrt3# and #y=2×sin((7pi)/6)=2×(-1/2)=-1#.

Hence to plot #(2,(7pi)/6)# , one should plot point #(-sqrt3,-1)#.

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