How do you plot the polar coordinate $(2, (7pi)/6)$ ?

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Answer 1 · 2017-04-14T08:55:26

To plot $(2,(7pi)/6)$ , one should plot point $(-sqrt3,-1)$ in Cartesian plane.

The relation between polar coordinate $(r,theta)$ and Cartesian coordinates $(x,y)$ is

$x=rcostheta$ and $y=rsintheta$

Hence for $(2,(7pi)/6)$ we have $x=2×cos((7pi)/6)=2×(-sqrt3/2)=-sqrt3$ and $y=2×sin((7pi)/6)=2×(-1/2)=-1$ .

Hence to plot $(2,(7pi)/6)$ , one should plot point $(-sqrt3,-1)$ .

How do you plot the polar coordinate (2, (7pi)/6)(2, (7pi)/6)?