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How do you plot the polar coordinate #(2, (11pi)/6)#?

1 Answer

Harish Chandra Rajpoot

Jul 5, 2018

The given polar coordinates #(r, \theta)\equiv (2, {11\pi}/6)# has the following Cartesian coordinates

#x=r\cos\theta=2\cos({11\pi}/6)=2\cos(\pi/6)=2\cdot\sqrt3/2=\sqrt3#

#y=r\sin\theta=2\sin({11\pi}/6)=-2\sin(\pi/6)=-2\cdot1/2=-1#

Now, take #x=\sqrt3# units on +ve axis & #y=1# unit on -ve y-axis to specify the location of given point

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