How do you perform the operation and write the result in standard form given (6-2i)(2-3i)?

1 Answer
Nov 27, 2016

6-22i

Explanation:

The standard form is color(blue)a+color(red)bi

(6-2i)(2-3i)=12-18i-4i+6i^2

Add like terms

=12-22i+6i^2

Apply the definition i^2=-1

=12-22i+6(-1)
=12-22i-6
=color(blue)(6)color(red)-color(red)22i