How do you name cycloalkanes with double bonds?

Nomenclature is naming.

Nomenclature of cyclic or circular molecules involves counting the number of carbon atoms and giving it the appropriate root (e.g. 6 #-># 'hex-', 4 #-># 'but-') and adding 'cyclo-' as a prefix.

For example, a circular molecule with five carbon atoms and two double bonds between carbon numbers 1-2 and 3-4 would be

cyclopenta-1,3-diene

The nomenclature of alkenes is fairly straight forward.

root + where DB's are + number of DB's + ene

In the case above, cyclopenta-1,3-diene, 'penta-' is the root, '-1,3-' is where the double bonds are located, '-di-', from the Latin for two, is how many double bonds there are, and '-ene' is the suffix for an alkene.

More examples are

cycloprop-1-ene or simply cyclopropene #-># three carbon atoms in a triangular form, with one double bond on the first carbon.

cyclohepta-1,2,5-triene #-># seven carbon atoms, with three double bonds between atoms 1-2, 2-3 and 5-6 in a heptagon format.

cyclobuta-1,3-diene #-># four carbon atoms with two double bonds between atoms 1-2 and 3-4 in a quadrilateral.