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How do you multiply #(x-4)(x+8)#?

1 Answer

Aug 2, 2015

#(x-4)(x+8)=x^2+4x-32#

Explanation:

Use the FOIL method which shows the order of multiplication of the terms. Then add like terms.

#(x-4)(x+8)=(x*x)+(x*8)+(-4*x)+(-4*8)# =

#(x-4)(x+8)=x^2+8x-4x-32# =

#(x-4)(x+8)=x^2+4x-32#

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