How do you multiply $(x^(3/2) + 2/sqrt3)^2$ ?

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Answer 1 · 2017-06-09T19:12:07

See a solution process below:

This is a special form of quadratic:

$(a + b)^2 = a^2 + 2ab + b^2$

Substituting $x^(3/2)$ for $a$ and $2/sqrt(3)$ for $b$ gives:

$(x^(3/2) + b)^2 = (x^(3/2))^2 + (2 * x^(3/2) * 2/sqrt(3)) + (2/sqrt(3))^2 =$

$x^3 + (4x^(3/2))/sqrt(3) + 4/3$

How do you multiply (x^(3/2) + 2/sqrt3)^2 (x^(3/2) + 2/sqrt3)^2?