How do you multiply $(x - 2) (x - 3)$ $(x-2)(x-3)$ ?

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Answer 1 · 2018-07-21T16:05:04

$x^{2} - 5 x + 6$ $x^2-5x+6$

We can use the highly useful mnemonic FOIL (Firsts, Outsides, Insides, Lasts). This is the order we multiply in. We get

Putting it all together, we get

$x^{2} - 3 x - 2 x + 6$ $x^2-3x-2x+6$ , or $x^{2} - 5 x + 6$ $x^2-5x+6$

Hope this helps!

Answer 2 · 2018-07-21T16:09:31

$x^{2} - 5 x + 6$ $x^2-5x+6$

$(x - 2) (x - 3)$ $(x-2)(x-3)$

$= (x - 2) \cdot x - (x - 2) \cdot 3$ $=(x-2)\cdot x-(x-2)\cdot 3$

$= x^{2} - 2 x - 3 x + 6$ $=x^2-2x-3x+6$

$= x^{2} - 5 x + 6$ $=x^2-5x+6$

How do you multiply (x-2)(x-3)(x−2)(x−3)(x-2)(x-3)?