How do you multiply #x^ { 2} \cdot x ^ { 8} \cdot x #?

2 Answers
David Drayer
May 25, 2018

Add the exponents # x ^ (2 +8 +1)# = # x^11#

Explanation:

# x^2 = x xx x#
# x^8 = x xx x xx x xx x xx x xx x xx x xx x#
# x = x^1 = 1 xx x #

Add all the x's ( 2 + 8 + 1)

By adding all the exponents to multiply

# x ^ (2 + 8 +1) = x^11#

Ar Buh - Ort · Stefan V.
May 25, 2018

The answer is #x^11#.

Explanation:

When one has the same number but with several different exponents, the multiplication of the values is the addition of the exponents. In this case, it would be

#2 + 8 + 1#

which would equal #11#.

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