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How do you multiply #(t-3)(t^2+3t+9)#?

1 Answer

Apr 27, 2017

#=t^3-27#

Explanation:

#a^3-b^3=(a-b)(a^2+ab+b^2)#

Similarly

#(t-3)(t^2+3t+9)# can be written as

#t^3-3^3#

#=t^3-27#

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