How do you multiply $sqrt2(3sqrt14 - sqrt7)$ ?

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Answer 1 · 2018-03-27T00:33:25

$6sqrt7-sqrt14$

Multiply $sqrt2$ by each term in the parentheses

$sqrt2(3sqrt14-sqrt7)$

$sqrt2*3sqrt14-sqrt2*sqrt7$

$3sqrt28-sqrt14 rarr 3sqrt28$ can be simplified

$3sqrt28=3sqrt4*sqrt7 rarr$ $4$ is a perfect square

$6*sqrt7=6sqrt7=3sqrt28$

$6sqrt7-sqrt14$

How do you multiply sqrt2(3sqrt14 - sqrt7)sqrt2(3sqrt14 - sqrt7)?