How do you multiply ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9)^2$ and write the product in simplest form?

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How do you multiply ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9)^2$ and write the product in simplest form?

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Answer 1 · 2015-03-24T02:01:38

You can write (considering that ${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a-b)^2=a^2-2ab+b^2$ ):

$(\sqrt{10} - 9) \cdot (\sqrt{10} - 9) = {(\sqrt{10})}^{2} - 2 \cdot 9 \cdot \sqrt{10} + 9^{2} =$ $(sqrt(10)-9)*(sqrt(10)-9)=(sqrt(10))^2-2*9*sqrt(10)+9^2=$
$= 10 - 18 \sqrt{10} + 81 =$ $=10-18sqrt(10)+81=$
$= 91 - 18 \sqrt{10} =$ $=91-18sqrt(10)=$

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How do you multiply ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9)^2$ and write the product in simplest form?

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How do you multiply (sqrt10 - 9)^2(√10−9)2(sqrt10 - 9)^2 and write the product in simplest form?

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How do you multiply ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9)^2$ and write the product in simplest form?