How do you multiply #sqrt (x) * (x)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Olivier B. Jun 13, 2015 #sqrtx*x=sqrt(x^3)# Explanation: Knowing that #sqrtx=x^(1/2)# and using the properties: #x^a*x^b=x^(a+b)# #(x^a)^b=x^(a*b)# you have: #sqrtx*x=x^(1/2)*x^1=x^(1/2+1)=x^(3/2)=(x^3)^(1/2)=sqrt(x^3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1586 views around the world You can reuse this answer Creative Commons License