How do you multiply #sqrt 8 * 2 #? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Serena D. · Hriman Apr 10, 2018 #4sqrt2# Explanation: Put the #2# in front of radical 8 #2sqrt(8)=# #2sqrt(2*4)=# #4sqrt2# 2 is not part of the radical so it must go in front. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1177 views around the world You can reuse this answer Creative Commons License