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How do you multiply #(m - 1) (m^2 + 2m + 6)#?

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Apr 13, 2015

First you multiply the #m# with all the others in the second group, and then the #-1#

#=m*(m^2+2m+6)+(-1)*(m^2+2m+6)#

#=(m.m^2+m*2m+m*6)+(-1m^2-2m-6)#

#=m^3+2m^2+6m-1m^2-2m-6#. now add like powers:

#=m^3+(2-1)m^2+(6-2)m-6#

#=m^3+m^2+4m-6#

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