How do you multiply #(m - 1) (m^2 + 2m + 6)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer MeneerNask Apr 13, 2015 First you multiply the #m# with all the others in the second group, and then the #-1# #=m*(m^2+2m+6)+(-1)*(m^2+2m+6)# #=(m.m^2+m*2m+m*6)+(-1m^2-2m-6)# #=m^3+2m^2+6m-1m^2-2m-6#. now add like powers: #=m^3+(2-1)m^2+(6-2)m-6# #=m^3+m^2+4m-6# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1388 views around the world You can reuse this answer Creative Commons License