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How do you multiply and simplify the following expression completely #(x-2y)^3#?

1 Answer

Mar 24, 2015

The rule is:

#(a-b)^3=a^3-3a^2b+3ab^2-b^3#.

So:

#(x-2y)^3=x^3-3(x)^2(2y)+3x(2y)^2-(2y)^3=#

#=x^3-6x^2y+12xy^2-8y^3#.

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