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How do you multiply #(ab + bc)(ab + bc)#?

1 Answer

Mar 23, 2017

This can be done using the perfect square formula"

Explanation:

#(a + b)(a + b) = a^2 + 2ab + b^2#

Substituting #ab# for #a# and #bc# for #b# gives:

#(ab + bc)(ab + bc) = (ab)^2 + 2abbc + (bc)^2 =#

#a^2b^2 + 2ab^2c + b^2c^2#

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