How do you multiply $(a + b) (c + d)$ $(a + b)(c + d)$ ?

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Answer 1 · 2016-10-10T16:58:30

$(a + b) (c + d) = a c + b c + a d + b d$ $(a+b)(c+d)=ac+bc+ad+bd$

To multiply $(a + b) (c + d)$ $(a+b)(c+d)$ ,

let us first consider $(a + b)$ $(a+b)$ as single number

and applying distributive property.

$(a + b) (c + d)$ $(a+b)(c+d)$

= $(a + b) \times c + (a + b) \times d$ $(a+b)xxc+(a+b)xxd$

Now on each of the two i.e. $(a + b) \times c$ $(a+b)xxc$ and $(a + b) \times d$ $(a+b)xxd$

can again be simplified using distributive property, as follows

$a \times c + b \times c + a \times d + b \times d$ $axxc+bxxc+axxd+bxxd$

= $a c + b c + a d + b d$ $ac+bc+ad+bd$

How do you multiply (a + b)(c + d)(a+b)(c+d)(a + b)(c + d)?