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How do you multiply #(8p-2)(6p+2) #?

1 Answer

Jul 11, 2015

#(8p-2)(6p+2)=48p^2+4p-4#

Explanation:

Use the FOIL method which indicates the order in which the terms of each binomial are multiplied.

#(8p-2)(6p+2)# =

#(8p*6p)+(8p*2)+(-2*6p)+(-2*2)# =

#48p^2+16p-12p-4# =

#48p^2+4p-4#

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