How do you multiply #(6c-1)^2#?
1 Answer
Feb 13, 2017
Explanation:
Each term in the second bracket must be multiplied by each term in the first bracket. ThIs can be achieved as shown.
#(color(red)(6c-1))(6c-1)#
#=color(red)(6c)(6c-1)color(red)(-1)(6c-1)# distributing.
#=36c^2-6c-6c+1# collecting like terms.
#=36c^2-12c+1#
