How do you multiply #(-5+4i)(-2+2i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Alan N. Jul 31, 2016 #2-18i# Explanation: #z = (-5+4i)(-2+2i)# Expand #-># #z=10-10i-8i+8i^2# Since #i=sqrt(-1) ->i^2=-1# Therefore: #z = 10-18i-8 = 2-18i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 2657 views around the world You can reuse this answer Creative Commons License