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How do you multiply #-4i(3-5i)#?

1 Answer

Shwetank Mauria

Apr 17, 2016

#-4i(3-5i)=-20-12i#

Explanation:

#-4i(3-5i)=(-4i)xx3-(-4i)xx(5i)=-12i+20i^2#

It is assumed that #i# is not a variable, but is a unit imaginary number and hence #i^2=-1# and hence

#-4i(3-5i)=-12i+20i^2=-12i-20# or #-20-12i#

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