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How do you multiply #(3y^3+9y+27)(-3y^2)#?

1 Answer

Mar 17, 2017

See the entire solution process below:

Explanation:

Multiply each term in the parenthesis on the left by #color(red)(-3y^2)#:

#(color(red)(-3y^2) xx 3y^3) + (color(red)(-3y^2) xx 9y) + (color(red)(-3y^2) xx 27) =#

#-9y^5 - 27y^3 - 81y^2#

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