How do you multiply $(3y^3+9y+27)(-3y^2)$ ?

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Answer 1 · 2017-03-17T22:28:54

See the entire solution process below:

Multiply each term in the parenthesis on the left by $color(red)(-3y^2)$ :

$(color(red)(-3y^2) xx 3y^3) + (color(red)(-3y^2) xx 9y) + (color(red)(-3y^2) xx 27) =$

$-9y^5 - 27y^3 - 81y^2$

How do you multiply (3y^3+9y+27)(-3y^2)(3y^3+9y+27)(-3y^2)?