How do you multiply $(3 y^{3} + 9 y + 27) (- 3 y^{2})$ $(3y^3+9y+27)(-3y^2)$ ?

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How do you multiply $(3 y^{3} + 9 y + 27) (- 3 y^{2})$ $(3y^3+9y+27)(-3y^2)$ ?

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Answer 1 · 2017-03-17T22:28:54

See the entire solution process below:

Explanation:

Multiply each term in the parenthesis on the left by $- 3 y^{2}$ $color(red)(-3y^2)$ :

$(- 3 y^{2} \times 3 y^{3}) + (- 3 y^{2} \times 9 y) + (- 3 y^{2} \times 27) =$ $(color(red)(-3y^2) xx 3y^3) + (color(red)(-3y^2) xx 9y) + (color(red)(-3y^2) xx 27) =$

$- 9 y^{5} - 27 y^{3} - 81 y^{2}$ $-9y^5 - 27y^3 - 81y^2$

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How do you multiply $(3 y^{3} + 9 y + 27) (- 3 y^{2})$ $(3y^3+9y+27)(-3y^2)$ ?

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