How do you multiply #(3x-2)(x+5)#?
1 Answer
Apr 11, 2018
Explanation:
#"each term in the second factor is multiplied by each"#
#"term in the first factor"#
#rArr(color(red)(3x-2))(x+5)#
#=color(red)(3x)(x+5)color(red)(-2)(x+5)#
#=(color(red)(3x)xx x)+(color(red)(3x)xx5)+(color(red)(-2)xx x)+(color(red)(-2)xx5)#
#=3x^2color(blue)(+15x)color(blue)(-2x)-10#
#=3x^2+13x-10#