How do you multiply #(3x^2-5)(x^4-1)#?

1 Answer
smendyka
Jun 29, 2017

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3x^2) - color(red)(5))(color(blue)(x^4) - color(blue)(1))# becomes:

#(color(red)(3x^2) xx color(blue)(x^4)) - (color(red)(3x^2) xx color(blue)(1)) - (color(red)(5) xx color(blue)(x^4)) + (color(red)(5) xx color(blue)(1))#

#3x^6 - 3x^2 - 5x^4 + 5#

We can put the polynomial in standard form as:

#3x^6 - 5x^4 - 3x^2+ 5#

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