How do you multiply #(-3u+3)(u^3-1)#?

2 Answers
smendyka
Mar 30, 2017

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(-3u) + color(red)(3))(color(blue)(u^3) - color(blue)(1))# becomes:

#(color(red)(-3u) xx color(blue)(u^3)) + (color(red)(-3u) xx color(blue)(-1)) + (color(red)(3) xx color(blue)(u^3)) + (color(red)(3) xx color(blue)(-1))#

#-3u^4 + 3u + 3u^3 - 3#

#-3u^4 + 3u^3 + 3u - 3#

Jim G.
Mar 30, 2017

#-3u^4+3u^3+3u-3#

Explanation:

Each term in the second bracket must be multiplied by each term in the first bracket. This is demonstrated below.

#(color(red)(-3u+3))(u^3-1)#

#=color(red)(-3u)(u^3-1)color(red)(+3)(u^3-1)#

distribute brackets and simplify.

#=-3u^4+3u+3u^3-3#

#=-3u^4+3u^3+3u-3larrcolor(red)" in standard form"#

Related questions
See all questions in Multiplication of Polynomials by Binomials
Impact of this question
2740 views around the world
You can reuse this answer
Creative Commons License