How do you multiply #(-3j^7k^5)(-8jk^8)#?

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Answer 1 · 2015-04-10T08:45:26

#(-3j^7k^5)(-8jk^8)#

# = (-3*-8)*(j^7*j)*(k^5*k^8)#

# = 24*(j^7*j)*(k^5*k^8)#

In general, #color(blue)(a^m*a^n = a^(m+n)#

# = 24*(j^(7+1))*(k^(5+8))#

#color(green)( = 24*j^8*k^13#