How do you multiply $\frac{3 (x - 6)}{5} = \frac{3 (x + 2)}{6}$ $(3(x-6))/5=(3(x+2))/6$ ?

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Answer 1 · 2015-05-09T11:22:29

1) Multiplying the terms within brackets:

$\frac{3 x - 18}{5}$ $(3x- 18)/5$ $=$ $=$ $\frac{3 x + 6}{6}$ $(3x + 6)/6$

2) Cross multiplication:

$(3 x - 18) \times 6$ $(3x- 18) xx 6$ $=$ $=$ $(3 x + 6) \times 5$ $(3x + 6) xx 5$

$18 x - 108 = 15 x + 30$ $18x- 108 = 15x + 30$
$3 x = 138$ $3x = 138$

$x = 46$ $x = 46$

How do you multiply (3(x-6))/5=(3(x+2))/63(x−6)5=3(x+2)6(3(x-6))/5=(3(x+2))/6?