How do you multiply $(3 + sqrt3) (4 + 3sqrt3)$ ?

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Answer 1 · 2015-04-30T19:04:19

The answer is $21+13sqrt3$

Use the FOIL method.
![http://www.mathblaster.com/coolmath/articles/foil-multiplying-binomials]( useruploads.socratic.org )

$(3+sqrt3)(4+3sqrt3)$ =

$3*4+3*3sqrt3+4sqrt3+3sqrt3sqrt3$ =

$12+9sqrt3+4sqrt3+3*3$ =

$12+13sqrt3+9$ =

$21+13sqrt3$

How do you multiply (3 + sqrt3) (4 + 3sqrt3)(3 + sqrt3) (4 + 3sqrt3)?