How do you multiply #(3 + sqrt3) (4 + 3sqrt3)#?

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Answer 1 · 2015-04-30T19:04:19

The answer is #21+13sqrt3#

Use the FOIL method.

#(3+sqrt3)(4+3sqrt3)# =

#3*4+3*3sqrt3+4sqrt3+3sqrt3sqrt3# =

#12+9sqrt3+4sqrt3+3*3# =

#12+13sqrt3+9# =

#21+13sqrt3#