How do you multiply # (3-sqrt2)(4+sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. Jun 4, 2015 #(3-sqrt(2))(4+sqrt(2))# #=(3xx4)+(3xxsqrt(2))-(sqrt(2)xx4)-(sqrt(2)xxsqrt(2))# #=12+3sqrt(2)-4sqrt(2)-2# #=(12-2)+(3-4)sqrt(2)# #=10-sqrt(2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1026 views around the world You can reuse this answer Creative Commons License