How do you multiply $(3.8 \cdot 10^{4}) (5.5 \cdot 10^{- 1})$ $(3.810^4)(5.510^-1)$ ?

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How do you multiply $(3.8 \cdot 10^{4}) (5.5 \cdot 10^{- 1})$ $(3.810^4)(5.510^-1)$ ?

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Answer 1 · 2015-04-14T01:44:47

Multiply separately:
$3.8 \times 5.5 = 20.9$ $3.8xx5.5=20.9$
and $10^{4} \times 10^{- 1} =$ $10^4xx10^-1=$ remembering that $a^{m} \times a^{n} = a^{m + n}$ $a^mxxa^n=a^(m+n)$
So you get: $10^{4} \times 10^{- 1} = 10^{4 - 1} = 10^{3}$ $10^4xx10^-1=10^(4-1)=10^3$
Finally you get:
$20.9 \times 10^{3} = 2.09 \times 10^{4}$ $20.9xx10^3=2.09xx10^4$ moving the point to the left and adding 1 to the exponent of $10$ $10$ .

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How do you multiply $(3.8 \cdot 10^{4}) (5.5 \cdot 10^{- 1})$ $(3.810^4)(5.510^-1)$ ?

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