How do you multiply #(-3+5i)(-5+7i)#?

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How do you multiply #(-3+5i)(-5+7i)#?

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Answer 1 · 2017-01-11T01:54:36

# (-3+5i)(-5+7i) = -20-46i#

Explanation:

Multiplying out the brackets term by term gives:

# (-3+5i)(-5+7i) #
# \ \ \ \ \ = (-3)(-5) + (-3)(7i) + (5i)(-5)+(5i)(7i)#
# \ \ \ \ \ = 15-21i-25i+35i^2#
# \ \ \ \ \ = 15-46i+35i^2#
# \ \ \ \ \ = 15-46i-35 " " (because i^2=-1)#
# \ \ \ \ \ = -20-46i#

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How do you multiply #(-3+5i)(-5+7i)#?

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