How do you multiply $(2x-4)(x^2 -3x +10)$ ?

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Answer 1 · 2015-07-27T12:27:18

$=2x^3 −10x^2 +32x -40$

$color(blue)((2x−4))(x^2−3x+10)$

Here, we need to multiply each term within the first bracket with all the three terms of the second bracket.

$=color(blue)((2x))(x^2−3x+10) −(color(blue)(4))(x^2−3x+10)$

$=2x^3−6x^2+20x −4x^2 +12x-40$

Grouping like terms
$=2x^3 −4x^2−6x^2 +12x+20x -40$

$=2x^3 −10x^2 +32x -40$

How do you multiply (2x-4)(x^2 -3x +10)(2x-4)(x^2 -3x +10)?