How do you multiply # (2sqrt5)^2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ May 4, 2015 You may use the following: 1] #(x^a)^b=x^(a*b)# 2] #rootn(x^m)=x^(m/n)# In your case: #(2sqrt(5))^2=2^2*5^(1/2*2)=4*5=20# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 4322 views around the world You can reuse this answer Creative Commons License