How do you multiply #2i(4-5i)(4+5i)#?
1 Answer
May 25, 2018
Explanation:
#"expand the factors then multiply by "2i#
#["note "i^2=(sqrt(-1))^2=-1]#
#(4-5i)(4+5i)=16-25i^2=41#
#2ixx41=82i#
Precalculus
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