How do you multiply $(2a+3b)^2$ ?

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Answer 1 · 2016-05-20T01:49:49

Expand out the square so it's easier to see, then use the distributive property to arrive at
$4a^2+12ab+9b^2$

Let's first expand this out so that it's easier to see and work with:

$(2a+3b)^2$
$(2a+3b)(2a+3b)$

Now we use the distributive property which says that each term in the first bracket multiplies against each term in the second bracket, like this:

$2a*2a=4a^2$
$2a*3b=6ab$
$3b*2a=6ab$
$3b*3b=9b^2$

And now we add them all up

$4a^2+6ab+6ab+9b^2$

We can combine the 2 $6ab$ terms to arrive at

$4a^2+12ab+9b^2$

How do you multiply (2a+3b)^2(2a+3b)^2?