How do you multiply #(2a ^ { - 2} ) ^ { 3} ( a ^ { 4} a ^ { - 5} ) ^ { 6}#?

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Answer 1 · 2018-07-10T07:26:51

#8/a^(12)#

We have #(2a^(-2))^3(a^4*a^(-5))^6#
Note that #a^4*a^(-5)=a^(-1)#
and #(ab)^n=a^n*b^n# so we get

#2^3*a^(-6)*a^(-6)=8*a^(-12)=8/a^12#

Answer 2 · 2018-07-10T07:30:40

#8/a^12#

Given tha

#(2a^{-2})^3(a^4a^{-5})^6#

#=2^3a^{-2\cdot 3}(a^{-5+4})^6#

#=8a^{-6}(a^{-1})^6#

#=8a^{-6}\cdot a^{-6}#

#=8a^{-6-6}#

#=8a^{-12}#

#=8/a^12#