How do you multiply #((2, 8), (6, 3))# with #((3, 0), (2, -1))#? Precalculus Matrix Algebra Multiplication of Matrices 1 Answer VinÃcius Ferraz Jul 4, 2017 #((a_11, a_12),(a_21, a_22))# Explanation: The product is #A#. #a_11 = 2 * 3 + 8 * 2# #a_12 = 2 * 0 + 8(-1)# #a_21 = 6 * 3 + 3 * 2# #a_22 = 6 * 0 + 3(-1)# #A = ((22, -8),(24, -3))# Answer link Related questions What is multiplication of matrices? How do I do multiplication of matrices? What is scalar multiplication of matrices? What are some sample matrix multiplication problems? How do I multiply the matrix #((6, 4, 24),(1, -9, 8))# by 4? How do I multiply the matrix #((3, 0, -19),(0, 7, 1), (1, 1/5, 2/3))# by -6? How do I multiply the matrix #((6, 4, 24),(1, -9, 8))# by the matrix #((1, 5, 0), (3, -6, 2))#? Is matrix multiplication associative? If #A=((-4, 5),(3, 2))# and #B=((-6, 2), (1/2, 3/4))#, what is #AB#? In matrix multiplication, does ABC=ACB? See all questions in Multiplication of Matrices Impact of this question 1668 views around the world You can reuse this answer Creative Commons License