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How do you multiply #(2-4i)(3+5i)#?

1 Answer

Nov 12, 2016

# (2-4i)(3+5i) =26-2i #

Explanation:

# (2-4i)(3+5i) =(2)(3)+(2)(5i)+(-4i)(3)+(-4i)(5i) #
# :. (2-4i)(3+5i) =6+10i-12i-20i^2 #
# :. (2-4i)(3+5i) =6-2i-20i^2 #

Now #i^2=-1#, so
# :. (2-4i)(3+5i) =6-2i+20 #
# :. (2-4i)(3+5i) =6-2i+20 #
# :. (2-4i)(3+5i) =26-2i #

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