How do you multiply $12 a (a + b) (a + - 1 b)$ $12a(a + b)(a + -1b)$ ?

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How do you multiply $12 a (a + b) (a + - 1 b)$ $12a(a + b)(a + -1b)$ ?

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Answer 1 · 2017-12-12T08:11:00

$- 1 b = - b$ $-1b=-b$
You get
$12 a (a + b) (a - b)$ $12a(a+b)(a-b)$
The identity literally is:
$(a + b) (a - b) = a^{2} - b^{2}$ $(a+b)(a-b)=a^2-b^2$
You get
$12 a (a^{2} - b^{2})$ $12a(a^2-b^2)$
You should know that:
$12 a (a^{2} - b^{2}) \neq 12 a \times a^{2} - b^{2}$ $12a(a^2-b^2)!=12axxa^2-b^2$
Distribute it,
$a (x \pm \times \div y) = a \times x \pm \times \div a \times y$ $a(x+- xx div y)=axx x +-xx div axxy$
The $\pm \times \div$ $+-xxdiv$ means it could be anything in between
By using distributive property
$12 a \times a^{2} - 12 a \times b^{2}$ $12axxa^2-12axxb^2$
Remember,
$a^{m} \times a^{n} = a^{m + n}$ $a^mxxa^n=a^(m+n)$
$12 (a^{1 + 2}) - 12 a b^{2}$ $12(a^(1+2)) - 12ab^2$
You get
$12 a^{3} - 12 a b^{2}$ $12a^3-12ab^2$

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How do you multiply $12 a (a + b) (a + - 1 b)$ $12a(a + b)(a + -1b)$ ?

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How do you multiply 12a(a + b)(a + -1b)12a(a+b)(a+−1b)12a(a + b)(a + -1b)?

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How do you multiply $12 a (a + b) (a + - 1 b)$ $12a(a + b)(a + -1b)$ ?