How do you multiply # 1/4 * sqrt(72)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise May 21, 2015 #sqrt(72) = sqrt(9.4.2)# #sqrt(9.4.2) = 3.2sqrt2 = 6sqrt2# multiplying: # 1/4 * sqrt(72) = 1/4 . 6sqrt2# # 1/4 . 6sqrt2 = (3sqrt2)/2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1142 views around the world You can reuse this answer Creative Commons License