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How do you multiply # (-1+2i)(3+2i) # in trigonometric form?

1 Answer

Ratnesh Bhosale

Dec 30, 2017

#-7+4iota#

Explanation:

#iota= sqrt(-1)#
So, #iota^2=-1#

#(-1+2iota) (3+2iota)#

#-3-2iota+6iota-4#

#-7+4iota#

Simply multiply as we generally multiply polynomial by polynomial provided the rules of complex must in mind just like #iota^2=-1#.

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