How do you locate the absolute extrema of the function on the closed interval $y = 3 - | x - 3 |$ $y = 3 - abs(x - 3)$ , on the interval [-1, 5]?

Question

How do you locate the absolute extrema of the function on the closed interval $y = 3 - | x - 3 |$ $y = 3 - abs(x - 3)$ , on the interval [-1, 5]?

1 Answer

Impact of this question

3860 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-21T07:54:27

Find the first derivative and any critical values.
Find the y-value for each critical value and the y-value at the endpoints. The largest is abs. max, the smallest is abs min.

Explanation:

Note, the graph of any absolute value equation has a V shape, this one is upside down, shifted right 3 units and up 3 units. The corner of the V is at x = 3.
$f (- 1) = - 1$ $f(-1)=-1$ the absolute min
$f (3) = 3$ $f(3)=3$ the absolute max
$f (5) = 1$ $f(5)=1$

Science

Math

Humanities

... and beyond

How do you locate the absolute extrema of the function on the closed interval $y = 3 - | x - 3 |$ $y = 3 - abs(x - 3)$ , on the interval [-1, 5]?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you locate the absolute extrema of the function on the closed interval y=3−|x−3|y = 3 - abs(x - 3), on the interval [-1, 5]?

1 Answer

Explanation:

Related questions

Impact of this question

How do you locate the absolute extrema of the function on the closed interval $y = 3 - | x - 3 |$ $y = 3 - abs(x - 3)$ , on the interval [-1, 5]?