How do you list all possible roots and find all factors of x^5+7x^3-3x-12?
1 Answer
Possible rational zeros are:
+-1, +-2, +-3, +-4, +-6, +-12
but none are actually zeros.
This quintic is not solvable using radicals and elementary functions.
Explanation:
Rational roots theorem
By the rational roots theorem, any rational zeros of
That means that the only possible rational zeros are:
+-1, +-2, +-3, +-4, +-6, +-12
Note that when
abs(7x^3)+abs(3x)+abs(12) <= abs(7x^3)+abs(3x)+abs(4x) = abs(7x^3)+abs(7x) < abs(7x^3)+abs(x^3) = abs(8x^3) < abs(x^5)
So no
Checking the other possible rational zeros, we find:
f(-2) = -32-56+6-12 = -94
f(-1) = -1-7+3-12 = -17
f(1) = 1+7-3-12 = -7
f(2) = 32+7-6-12 = 21
So
Quintic
In fact this is a typical quintic with
About the best you can do is find approximations using numerical methods such as Durand Kerner.
See https://socratic.org/s/aAGsRKkf for another example and a description of the Durand-Kerner algorithm for a quintic.
Using this algorithm, I found the following approximations:
x_1 ~~ 1.22622
x_(2,3) ~~ 0.101096+-2.734i
x_(4,5) ~~ -0.714207+-0.892944i
Here's the C++ program I used: