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How do you know if #S(x)=sin x/ x# is an even or odd function?

1 Answer

Nov 21, 2015

#S(x)# is an even function.

Explanation:

A function is EVEN if #f(-x)=f(x)#. A function is ODD if #f(-x)=-f(x)#.

Let's find #S(-x)#.

#S(-x)=stackrel"equal to -sin(x)"overbrace(sin(-x)/-x#

#S(-x)=(-sin(x))/-x#

#S(-x)=sin(x)/x=S(x)#

Thus, S(x) is an even function.

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