How do you know if f(x) = x^3 + x sin^2 xf(x)=x3+xsin2x is an even or odd function?
1 Answer
Nov 28, 2015
Use
Explanation:
f(-x) = (-x)^3+(-x)(sin(-x))^2f(−x)=(−x)3+(−x)(sin(−x))2
=-x^3-x(-sin(x))^2=−x3−x(−sin(x))2
=-x^3-x (sin(x))^2=−x3−x(sin(x))2
=-(x^3+x (sin(x))^2)=−(x3+x(sin(x))2)
=-f(x)=−f(x)