How do you know if f(x) = x^3 + x sin^2 xf(x)=x3+xsin2x is an even or odd function?

1 Answer
Nov 28, 2015

Use sin(-x) = -sin(x)sin(x)=sin(x) and find f(-x) = -f(x)f(x)=f(x) so ff is odd.

Explanation:

f(-x) = (-x)^3+(-x)(sin(-x))^2f(x)=(x)3+(x)(sin(x))2

=-x^3-x(-sin(x))^2=x3x(sin(x))2

=-x^3-x (sin(x))^2=x3x(sin(x))2

=-(x^3+x (sin(x))^2)=(x3+x(sin(x))2)

=-f(x)=f(x)