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How do you integrate #int tanx# using substitution?

1 Answer

Jul 19, 2016

#int tanx dx = -ln(cosx) + C#

Explanation:

#tanx = sinx/cosx#

#int sinx/cosx dx#

Let #u = cosx implies du = -sinxdx#

#therefore -int (du)/u = -ln(u) + C#

#therefore int tanx dx = -ln(cosx) + C#

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